![]() ![]() Python One-Liners Book: Master the Single Line First! Thus, changing the value of a in this case means we are creating a new object without touching the previously created object that was being referred by a, b and c. It is evident that after rebinding a new value to the variable a, it points to a different memory location, hence it now refers to a different object. Here, the value being changed is an interger and integers are immutable.įollow the given illustration to visualize what’s happening in this case: This means, you are changing it in-place and that leads to a now pointing at a completely different value at a different location. However, in the second case you are rebinding a different value to the variable a. To create a new object and assign it, you must use the copy module as shown below: import copy Thus the changes are reflected for b and c both along with a. This means you are making the changes to the same object that also has the names b and c. Thus, in the first case when you make a change at a certain index of variable a, i.e, a = 1. This means, a, b and c are not different variables with same values rather they are different names given to the same object. So, when you chain multiple variables as in the above case all of them refer to the same object. Remember that everything in Python is treated as an object. a=b=c=īut, why does the following assignment lead to a different behaviour? a = b = c = 5 Problem: I tried to use multiple assignment as show below to initialize variables, but I got confused by the behavior, I expect to reassign the values list separately, I mean b and c equal 0 as before. Let’s address a frequently asked question that troubles many coders. ➡ value is an optional parameter that represents the values for all the keys in the new dictionary. ➡ keys is a required parameter that represents an iterable containing the keys of the new dictionary. Thus, changes to a particular variable will not affect another variable as shown below: variable_list = įromkeys() is a dictionary method that returns a dictionary based on specified keys and values passed within it as parameters. This is on account that each variable acts as a key of the dictionary and every key in a dictionary is unique. However, each variable occupies a different memory location. Method 2: Using omkeysĪpproach: Use the omkeys(variable_list, val) method to set a specific value ( val) to a list of variables ( variable_list).ĭiscussion: It is evident from the above output that each variable assigned holds the same value. It is evident from the above output that each variable has been assigned the same value and each of them point to the same memory location. Print("All variables point to the same memory location:")Īll variables point to the same memory location: Syntax: variable_1 = variable_2 = variable_3 = value You can use chained equalities to declare the variables and then assign them the required value. Python One-Liners Book: Master the Single Line First!. ![]()
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